Circuit Analysis II

Circuit Analysis II

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Intermediate level electrical engineering textThen, since in general adB = 20logb, and that y = logx implies x = j(r , we have HP 14 m 10 = 0.25 and therefore 1f we wish to ... we get g5000=0.01 1 *5000j/((1 +50j}* fprintf(a#39;\na#39;); fprintf(a#39;mag = %6.2f \ta#39;, abs(g5000));... fprintf(a#39;phase = %6.2f deg.


Title:Circuit Analysis II
Author: Steven T. Karris
Publisher:Orchard Publications - 2003
ISBN-13:

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